ANSYS基础培训练习题第六天

l,5,6

l,6,7

l,7,8

l,8,5

l,9,5

l,9,6

l,9,7

l,9,8

lsel,,loc,y,0,119       ! 按位置(Y)选择立柱(线)

cm,lvert,line         ! 定义部件Vertical lines

lsel,,loc,y,120        !选择水平横梁

cm,lhoriz,line        ! Horizontal lines

lsel,,loc,y,121,180    !选择顶梁

cm,lslope,line       ! Sloping lines

lsel,all             !选择所有线

et,1,188  !定义188梁单元

mp,ex,1,2e6    !定义弹性模量

mp,nuxy,1,0.3

mp,dens,1,7800

sectype,1,beam,i,beam                 !定义第一种截面为工字梁

secdata,6.535,6.535,8.06,.465,.465,.285   !定义梁截面尺寸

sectype,2,beam,i,column               !定义第二种截面为工字梁

secdata,12,12,12.12,.605,.605,.39        !定义梁截面尺寸

sectype,3,beam,hrec,peak              !定义第三种种截面为口字梁

secdata,6,6,.25,.25,.25,.25              !定义梁截面尺寸

save,frame,db

cmsel,,lslope        ! Sloping lines

latt,1,,1,,100,,3  ! 顶梁的截面号为3,方向关键点为100

cmsel,,lvert

lsel,r,loc,x,-90     ! Left vertical lines

latt,1,,1,,102,,2  ! 左侧的垂直梁(线1、4)截面号为2,方向关键点为102

cmsel,,lvert

lsel,r,loc,x,90      ! Right vertical lines

latt,1,,1,,101,,2  ! 右侧的垂直梁(线2、3)截面号为2,方向关键点为101

cmsel,,lhoriz

lsel,u,loc,z,-60

lsel,u,loc,x,90      ! Left and front horizontal lines

latt,1,,1,,1,,1    ! 左前水平梁(线5、8)截面号为1,方向关键点为1

cmsel,,lhoriz

lsel,u,loc,z,60

lsel,u,loc,x,-90     ! Right and back horizontal lines

latt,1,,1,,3,,1   ! 右后水平梁(线6、7)截面号为1,方向关键点为3

lsel,all

lesize,all,20   ! 所有的线分割数都为20

lmesh,all      !对所有的线划分网格

nsel,,loc,y,0    !选择y=0处的所有节点

d,all,all        ! 约束全部自由度Fix bottom nodes

ksel,all        !选择所有关键点  !

fk,9,fy,-10000  !给关键点9加-10000的Y方向的集中力

alls          !选择所有实体及有限元节点和单元

/solu         !进入SOLUTION

solve         !求解

后处理

打开单元形状显示,查看变形及应力结果。

  1.  利用前面的轴承座模型进行扩展后处理的讲解

具体体会路径操作,单元表的使用,等值图的画法,标注、切片图等技术

  1.  梁壳实体单元混合使用分析(命令流)具体讲解

问题描述:广告牌承受风载荷的模拟

采用单元:

SOLID45

SHELL181

BEAM188

约束为两立柱的底部节点全部约束

风载全部加在壳单元的面上

材料均为钢材

以下为该例题的命令流

fini

/cle

/title, mult-element in a model

/filname,ele_test,1

/prep7

ET,1,SHELL181   

ET,2,SOLID45

ET,3,BEAM188

R,1,0.05  

r,2,0

SECTYPE,1,BEAM,CSOLID,se1 

SECOFFSET, CENT 

SECDATA,0.2,8,0,0,0,0,0,0,0,0   

mp,ex,1,2e11

mp,dens,1,7800

mp,mu,1,0.3

mp,nuxy,1,0.3

rect,0,4,,3

block,,4,-.5,0,,0.5

block,,4,-.5,0,,-0.5

k,,0,-5,0

k,,4,-5,0

k,,5,-5,0

nummrg,kp

l,6,21

l,8,22

wpoff,,-0.1

wprot,,90

vsbw,all

wpoff,,,0.3

vsel,s,,,3,5,2

vsbw,all

alls

nummrg,all

lsel,s,,,5,7

lsel,a,,,21

LATT,1,2,3,,23,,1

asel,s,,,1,18,17

AATT,1,1,1,0

vsel,all

VATT,1,1,2,0

alls

WPCSYS,-1,0

lsel,s,loc,x,0.01,4-0.01

lesi,all,,,12,1

lsel,s,loc,y,0.01,2-0.01

lesi,all,,,8,2.5

lsel,a,loc,y,-.5-0.01,-5+0.01

lesi,all,,,10,3

alls

lesi,4,,,8,1/2.5

esize,0.05

asel,s,loc,z,0

asel,r,loc,y,-0.1,2

amesh,all

alls

lsel,s,loc,x,0

lsel,a,loc,x,4

lsel,r,loc,z,0

lsel,r,loc,y,-0.4,-5

lmesh,all

alls

vsel,all

vmesh,all

alls

asel,s,loc,y,0+0.01,2

sfa,all,1,pres,100

alls

nsel,s,loc,y,-5

d,all,all

alls

save

/solu

solve

fini

/post1

PLNSOL,S,EQV,0,1

ANCNTR,10,0.5

第四日 练习主题:巩固APDL基础、热应力及模态分析内容

1.弹簧建模

!This example demo modeling a ring using APDL

fini

/cle

/filname,ring,1

/prep7

*AFUN,DEG

TOT=12

N=TOT*3

et,1,45

et,2,200

keyopt,2,1,6

DIV=360/TOT

DIS=0.6/TOT

rid=1

rid2=0.1

csys,1

*DO,I,1,N+1

k,I,rid,(I-1)*DIV,(I-1)*DIS

*ENDDO

flst,3,n+1,3

*do,i,1,n+1

fitem,3,i

*enddo

bsplin,,p51x

ldiv,1,,,3

csys,0

wprot,,90

wpoff,ridpcirc,rid2,,0,360

asel,all

lsla,s

lesi,all,,,4

type,2

mshkey,0

amesh,all

type,1

extopt,esize,60

vdrag,1,,,,,,1

vdrag,6,,,,,,2

vdrag,11,,,,,,3

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